The quest to be named Champion Golfer of the Year begins next week at Royal Portrush. adidas is making sure Dustin Johnson, Xander Schauffele and Sergio Garcia are ready.
adidas Golf has today announced the apparel that the players will be wearing at the 148th Open Championship, debuting polos from adidas’ Autumn/Winter 2019 line...
World No. 2 Dustin Johnson will be making his 11th start in The Open Championship and will look to incorporate some new blue colourways to his style.
He will be kicking off the test for his second major in the Ultimate365 Gradient Polo in his traditional collegiate navy colourway, which he
will also wear in white and tech ink on Friday and Sunday, respectively.On Saturday, he will wear the Ultimate Colour Block Polo in a new shade - glow blue.
DJ will be completing his outfits with the industry-leading Ultimate365 Tapered and non-tapered pant.
Full info around DJ’s style can be found here.
Coming off a T-3 finish at the U.S. Open, Xander Schauffele is looking to continue his strong play at the majors, building off last year’s T-2 finish at The Open Championship.
Like his bold play on the course, Xander will be wearing bold colourways at Royal Portrush. He’ll be wearing the Ultimate365 2.0 Heather Polo in coral on Thursday and in tech ink on Saturday.
On Friday and Sunday, Xander will be wearing the Climachill Tonal Stripe Polo in collegiate navy and glow blue, respectively.
He will also pair his polos with the Ultimate365 Tapered and non-tapered pant.
Xander’s looks can be found here.
Sergio Garcia has 10 career top-10s at The Open Championship in his career, and he’ll be looking to add his second major at Royal Portrush.
No stranger to bold style, Sergio will wear the Ultimate365 Gradient Block Stripe Polo in tech ink and hi-res coral on Thursday and Friday.
For the weekend, Sergio will wear the Ultimate365 Heather Blocked Polo in grey on Saturday and tech ink on Sunday.
Sergio will finish off his look by wearing the Ultimate365 Pant in tapered and non-tapered styles.
Sergio’s apparel can be found here.